12x^2+25x-50=0

Solution for 12x^2+25x-50=0 equation:

12x^2+25x-50=0

a = 12; b = 25; c = -50;
Δ = b2-4ac
Δ = 252-4·12·(-50)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-55}{2*12}=\frac{-80}{24}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+55}{2*12}=\frac{30}{24}
=1+1/4
$